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Graphing Points & Linear Relationships — Easy Worksheet 1
Grade 8 · MathSheets Name: ____________________ Date: __________
Answer each question.
How to solve
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Example
Which quadrant is point P(-10, 1) in? (I, II, III or IV)
Answer: II
Not quite. The answer is
💡 x = 7 is positive and y = 6 is positive, so P is right of the y-axis and above the x-axis. That is Quadrant I.
✓ Correct!
Not quite. The answer is
💡 x = 7 is positive and y = 6 is positive, so P is right of the y-axis and above the x-axis. That is Quadrant I.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(8, -5) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Put x = 0 into y = x + 1: y = 0 + 1 = 1. So y = 1.
✓ Correct!
Not quite. The answer is
💡 Put x = 0 into y = x + 1: y = 0 + 1 = 1. So y = 1.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(9, 9) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 x = 6 is positive and y = −1 is negative, so P is right of the y-axis and below the x-axis. That is Quadrant IV.
✓ Correct!
Not quite. The answer is
💡 x = 6 is positive and y = −1 is negative, so P is right of the y-axis and below the x-axis. That is Quadrant IV.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(-7, 1) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Put x = 2 into y = x + 2: y = 2 + 2 = 4. So y = 4.
✓ Correct!
Not quite. The answer is
💡 Put x = 2 into y = x + 2: y = 2 + 2 = 4. So y = 4.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(7, 7) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 x = −1 is negative and y = 10 is positive, so P is left of the y-axis and above the x-axis. That is Quadrant II.
✓ Correct!
Not quite. The answer is
💡 x = −1 is negative and y = 10 is positive, so P is left of the y-axis and above the x-axis. That is Quadrant II.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(-10, 4) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Put x = 5 into y = 2x − 4: y = 2(5) − 4 = 10 − 4 = 6. So y = 6.
✓ Correct!
Not quite. The answer is
💡 Put x = 5 into y = 2x − 4: y = 2(5) − 4 = 10 − 4 = 6. So y = 6.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(-2, -7) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 x = −3 is negative and y = −9 is negative, so P is left of the y-axis and below the x-axis. That is Quadrant III.
✓ Correct!
Not quite. The answer is
💡 x = −3 is negative and y = −9 is negative, so P is left of the y-axis and below the x-axis. That is Quadrant III.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(2, 3) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Put x = 2 into y = x: y = 2. So y = 2.
✓ Correct!
Not quite. The answer is
💡 Put x = 2 into y = x: y = 2. So y = 2.
💡 How to solve: Graphing Points & Linear Relationships
For quadrants, check the signs: (+, +) is I, (-, +) is II, (-, -) is III, and (+, -) is IV. For an equation like y = mx + b, substitute the given x-value, multiply by m, then add b.
Try a similar one
Which quadrant is point P(-3, -2) in? (I, II, III or IV)
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
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Graphing Points & Linear Relationships — Easy Worksheet 1
Answer each question.