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Division with Remainders — Easy Worksheet 2
Grade 4 · MathSheets Name: ____________________ Date: __________
Answer each question. Write a quotient with its remainder like 13 R2.
How to solve
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Example
88 ÷ 5 = ___
Answer: 17 R3
Warm-up
Not quite. The answer is
💡 Divide 37 ÷ 4 = 9; multiply 9 × 4 = 36; subtract 37 − 36 = 1. Nothing is left to bring down, so 1 is the remainder: 37 ÷ 4 = 9 R1.
✓ Correct!
Not quite. The answer is
💡 Divide 37 ÷ 4 = 9; multiply 9 × 4 = 36; subtract 37 − 36 = 1. Nothing is left to bring down, so 1 is the remainder: 37 ÷ 4 = 9 R1.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
28 ÷ 3 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Divide 5 ÷ 4 = 1; multiply 1 × 4 = 4; subtract 5 − 4 = 1. Bring down the 3 to make 13. Divide 13 ÷ 4 = 3; multiply 3 × 4 = 12; subtract 13 − 12 = 1. Nothing is left to bring down, so 1 is the remainder: 53 ÷ 4 = 13 R1.
✓ Correct!
Not quite. The answer is
💡 Divide 5 ÷ 4 = 1; multiply 1 × 4 = 4; subtract 5 − 4 = 1. Bring down the 3 to make 13. Divide 13 ÷ 4 = 3; multiply 3 × 4 = 12; subtract 13 − 12 = 1. Nothing is left to bring down, so 1 is the remainder: 53 ÷ 4 = 13 R1.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
113 ÷ 6 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Divide 7 ÷ 4 = 1; multiply 1 × 4 = 4; subtract 7 − 4 = 3. Bring down the 3 to make 33. Divide 33 ÷ 4 = 8; multiply 8 × 4 = 32; subtract 33 − 32 = 1. Nothing is left to bring down, so 1 is the remainder: 73 ÷ 4 = 18 R1.
✓ Correct!
Not quite. The answer is
💡 Divide 7 ÷ 4 = 1; multiply 1 × 4 = 4; subtract 7 − 4 = 3. Bring down the 3 to make 33. Divide 33 ÷ 4 = 8; multiply 8 × 4 = 32; subtract 33 − 32 = 1. Nothing is left to bring down, so 1 is the remainder: 73 ÷ 4 = 18 R1.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
50 ÷ 6 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Picture it
Not quite. The answer is
💡 Divide each part by 3: 30 ÷ 3 = 10, 27 ÷ 3 = 9. Add the answers: 10 + 9 = 19. The 1 left over is the remainder. So 58 ÷ 3 = 19 R1.
✓ Correct!
Not quite. The answer is
💡 Divide each part by 3: 30 ÷ 3 = 10, 27 ÷ 3 = 9. Add the answers: 10 + 9 = 19. The 1 left over is the remainder. So 58 ÷ 3 = 19 R1.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
59 ÷ 5 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Think it through
Not quite. The answer is
💡 Divide 3 ÷ 3 = 1; multiply 1 × 3 = 3; subtract 3 − 3 = 0. Bring down the 8. Divide 8 ÷ 3 = 2; multiply 2 × 3 = 6; subtract 8 − 6 = 2. Nothing is left to bring down, so 2 is the remainder: 38 ÷ 3 = 12 R2.
✓ Correct!
Not quite. The answer is
💡 Divide 3 ÷ 3 = 1; multiply 1 × 3 = 3; subtract 3 − 3 = 0. Bring down the 8. Divide 8 ÷ 3 = 2; multiply 2 × 3 = 6; subtract 8 − 6 = 2. Nothing is left to bring down, so 2 is the remainder: 38 ÷ 3 = 12 R2.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
31 ÷ 6 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Find how many groups of 3 fit in 56: divide. Divide 5 ÷ 3 = 1; multiply 1 × 3 = 3; subtract 5 − 3 = 2. Bring down the 6 to make 26. Divide 26 ÷ 3 = 8; multiply 8 × 3 = 24; subtract 26 − 24 = 2. Nothing is left to bring down, so 2 is the remainder: 56 ÷ 3 = 18 R2. That is 18 full jars and 2 left over.
✓ Correct!
Not quite. The answer is
💡 Find how many groups of 3 fit in 56: divide. Divide 5 ÷ 3 = 1; multiply 1 × 3 = 3; subtract 5 − 3 = 2. Bring down the 6 to make 26. Divide 26 ÷ 3 = 8; multiply 8 × 3 = 24; subtract 26 − 24 = 2. Nothing is left to bring down, so 2 is the remainder: 56 ÷ 3 = 18 R2. That is 18 full jars and 2 left over.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
41 ÷ 6 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Divide 3 ÷ 2 = 1; multiply 1 × 2 = 2; subtract 3 − 2 = 1. Bring down the 5 to make 15. Divide 15 ÷ 2 = 7; multiply 7 × 2 = 14; subtract 15 − 14 = 1. Nothing is left to bring down, so 1 is the remainder: 35 ÷ 2 = 17 R1. The 17 full boxes hold 17 × 2 = 34 pencils, and 35 − 34 = 1 are left over.
✓ Correct!
Not quite. The answer is
💡 Divide 3 ÷ 2 = 1; multiply 1 × 2 = 2; subtract 3 − 2 = 1. Bring down the 5 to make 15. Divide 15 ÷ 2 = 7; multiply 7 × 2 = 14; subtract 15 − 14 = 1. Nothing is left to bring down, so 1 is the remainder: 35 ÷ 2 = 17 R1. The 17 full boxes hold 17 × 2 = 34 pencils, and 35 − 34 = 1 are left over.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
52 ÷ 3 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Challenge
Not quite. The answer is
💡 Undo the division by multiplying: 9 × 6 = 54. Then add the remainder: 54 + 4 = 58. The missing number is 58.
✓ Correct!
Not quite. The answer is
💡 Undo the division by multiplying: 9 × 6 = 54. Then add the remainder: 54 + 4 = 58. The missing number is 58.
💡 How to solve: Division with Remainders
Divide, multiply, subtract, bring down, and repeat. When no digits are left to bring down, the number left over is the remainder. It must be smaller than the divisor. Check: quotient × divisor + remainder = dividend.
Try a similar one
20 ÷ 3 = ___
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
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Division with Remainders — Easy Worksheet 2
Answer each question. Write a quotient with its remainder like 13 R2.