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Area & Perimeter of Polygons — Easy Worksheet 1
Grade 10 · MathSheets Name: ____________________ Date: __________
Solve each problem. Round to one decimal place if needed.
How to solve
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Example
Find the area of a rectangle with length 5 and width 9.
Answer: 45
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (6 + 4) = 2 × 10 = 20. The perimeter is 20.
✓ Correct!
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (6 + 4) = 2 × 10 = 20. The perimeter is 20.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the area of a rectangle with length 7 and width 4.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 5 × 7 = 35 ÷ 2 = 17.5. The area is 17.5.
✓ Correct!
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 5 × 7 = 35 ÷ 2 = 17.5. The area is 17.5.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the perimeter of a rectangle with length 4 and width 9.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (4 + 8) = 2 × 12 = 24. The perimeter is 24.
✓ Correct!
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (4 + 8) = 2 × 12 = 24. The perimeter is 24.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the area of a rectangle with length 5 and width 6.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 5 × 5 = 25 ÷ 2 = 12.5. The area is 12.5.
✓ Correct!
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 5 × 5 = 25 ÷ 2 = 12.5. The area is 12.5.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the perimeter of a rectangle with length 6 and width 4.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (6 + 5) = 2 × 11 = 22. The perimeter is 22.
✓ Correct!
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (6 + 5) = 2 × 11 = 22. The perimeter is 22.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the perimeter of a rectangle with length 3 and width 5.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 7 × 4 = 28 ÷ 2 = 14. The area is 14.
✓ Correct!
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 7 × 4 = 28 ÷ 2 = 14. The area is 14.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the perimeter of a rectangle with length 7 and width 9.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (5 + 8) = 2 × 13 = 26. The perimeter is 26.
✓ Correct!
Not quite. The answer is
💡 Perimeter of a rectangle = 2 × (length + width) = 2 × (5 + 8) = 2 × 13 = 26. The perimeter is 26.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the area of a rectangle with length 5 and width 7.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 9 × 9 = 81 ÷ 2 = 40.5. The area is 40.5.
✓ Correct!
Not quite. The answer is
💡 Area of a triangle = 12 × base × height = 12 × 9 × 9 = 81 ÷ 2 = 40.5. The area is 40.5.
💡 How to solve: Area & Perimeter of Polygons
For a rectangle, perimeter = 2 × (length + width) and area = length × width. For a triangle, area = 12 × base × height. Round to one decimal place if needed.
Try a similar one
Find the perimeter of a rectangle with length 9 and width 9.
✓ You've got it! Press Next to keep going. Not yet — the answer is . Read the steps above once more.
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Area & Perimeter of Polygons — Easy Worksheet 1
Solve each problem. Round to one decimal place if needed.